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Analog Electronics work with continuous variables, in such a way that a small modification in some variable can produce a great change in the behavior of the circuit, so here the variables will be real numbers. If you are a college student looking for quality Analog Electronics Assignment Help, we can assist you in every possible way. Using our computer science assignment help, you can easily complete all your academic assignments and save a lot of time and effort for other activities. We have over 5000+ specialists who are always ready to help you in any way and who can fulfill any of your educational needs. Everyone has a good academic record, and it can ease all your academic concerns. Our Analog Electronics assignment experts are well versed in the subject and can answer any questions you may have on any topic.

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An analog signal is one that takes all possible values between two-time intervals. For example, if we take the light intensity that exists between night and day, we see that it dawns little by little, continuously.

Analog Signal- Events in nature are presented in a continuous or analog way.

Analog electronics are in charge of treating electrical signals continuously. In the early days of electronics, all signals were treated this way, so all components were built to handle analog signals.

The transistor is possibly the most representative component, but it has already been studied in the subject of basic electronics. In this topic, we are going to study some concepts and a sample of the most used circuits.

We are going to study the concept of an amplifier, and as an example, we will see the operational amplifier, widely used in the early days of electronics. Then we will see the operation of the NE555, a very popular circuit. And finally, some components that are used in the control of alternating current.

In no case is it intended to give an exhaustive study of these components, but a few touches of their operation.

The Design Of A Power Supply Amplifier

A series of general concepts before passing a practical example.

Bearing in mind that in the case you must replace a rectifier valve due to running out substitute on an old receiver with a 1N4007 diode with a 47 Ohm series resistance leaving the old one in place. In practice, its equivalent circuit with semiconductors without compromising the historical value of the equipment remains with all its original parts, adding only has the mere function of restoring the device to function.

The design of modern amplifiers uses silicon diodes directly to their easy availability and increased efficiency.

The first capacitor after the rectifier stores most of the energy for the entire amplifier. Every half cycle rectified charges the capacitor voltage at peak AC with a short but large current pulse. The voltage then decreases when the charging current is continuously withdrawn from the amplifier circuit until it cannot be recharged.

The ripple voltage Vr is every so often expressed as a % of the maximum DC power. A typical figure might be 10% for a push-pull amplifier or 5% for a single-ended amplifier, although this is highly dependent on the individual needs of the circuits. Therefore, if you tip to a 400 V dc diet with 5% ripple, we don't want more than 400 — 0.05 = 20 ripple of the Vpp voltage. The main condenser can then be chosen roughly by the following formula:

C = I / (2 f Vr)

Where I is the average DC load current, f is the grid frequency (50 l to 60 Hz) and Vr is the desired peak-to-ripple voltage. This is a somewhat "conservative" formula; in practice, the ripple voltage will prove to be slightly lower than this. However, higher capacity also puts a strain on the rectifier and transformer, as it requires large pulses of current to hold the load. Most traditional amplifier projects use 22uF to 60uF if a tube rectifier or up to 220uF with silicon diodes are used (they rarely use higher values). Single-ended amplifiers require higher capacity as they do not cancel out hum like the push-pull amplifier.

If you need a high working voltage, the usual trick is to put two capacitors in series so that their voltage values are added.

However, the total capacity was halved, then two 100uF capacitors amount to 50uF. Also, resistors must be added in parallel to encourage the exchange of the same voltage between the capacitors. The resistors should be equal to 50 / C or name, then two 100uF capacitors would need a 500000-ohm resistor (470k would be the most obvious choice). These also serve discharge capabilities when the amplifier is turned off.

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